sicklittlemonkey wrote:
On May 4, 6:48 pm, Nama <forums6...@mac.com> wrote:If that is the case, then what would be the replacement for: (Q/2+Q^2/6+Q^3/12+Q^4/20+Q^5/30)Er, Q*(1/2+Q*(1/6+Q*(1/12+Q*(1/20+Q/30))))
And this is a substitution well worth making, since most microcomputer BASICs will compute integer powers by taking a natural log, multiplying by the power, then exponentiating--all of which takes a *long* time compared to a multiplication, a division, and an add! Of course the division by constants can be eliminated by doing it once outside the subroutine, making the cost of each term just one add and one multiply. -michael NadaNet 3.0 for Apple II parallel computing! Home page: http://home.comcast.net/~mjmahon/ "The wastebasket is our most important design tool--and it's seriously underused."