"Raymond Wiker" <raw@RawMBP.local> wrote in message news:m2mz41sgz3.fsf@RawMBP.local... > > Not *completely* sure, but I think that's wrong... AFAIR, it > should be e^(pi*i) = -1... Indeed e^(z*i) = cos(z) + i*sin(z) sin(pi)=0 cos(pi) = -1 -Alex.