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Re: Color Reference of NTSC Formula?
- Subject: Re: Color Reference of NTSC Formula?
- From: "Bryan Parkoff" <nospam@nospam.com>
- Date: Sun, 30 Jul 2006 18:07:54 GMT
- Newsgroups: comp.sys.apple2
- Organization: SBC http://yahoo.sbc.com
- References: <EJzyg.136572$dW3.66705@newssvr21.news.prodigy.com> <44cc66cf$0$1495$5a62ac22@per-qv1-newsreader-01.iinet.net.au>
- Reply-to: "Bryan Parkoff" <nospam@nospam.com>
- Xref: g2news2.google.com comp.sys.apple2:10936
"Mark McDougall" <msmcdoug@no.spam.iinet> wrote in message
news:44cc66cf$0$1495$5a62ac22@per-qv1-newsreader-01.iinet.net.au...
> Bryan Parkoff wrote:
>
>> Do you know the formula with cos / sine and the number of degree to
>> be translated into RGB signals?
>
> I believe this may be what you're after!?!
>
> <http://www.ntsc-tv.com/images/tv/vector.gif>
>
> Regards,
>
> --
> | Mark McDougall | "Electrical Engineers do it
> | <http://members.iinet.net.au/~msmcdoug> | with less resistance!"
Mark,
Thank you for the information. I have seen this before, but it does not
answer my question. I want to know how phase shift produces color. For
example, 16 colors below.
0000 0 Black No Luminance
1000 1 Deep Red 0 Degrees
0100 2 Dark Blue 90 Degrees
1100 3 Purple 45 Degrees
0010 4 Dark Green 180 Degrees
1010 5 Dark Gray 50% Luminance
0110 6 Medium Blue 135 Degrees
1110 7 Light Blue 90 Degrees, Luminance of "3"
0001 8 Brown 270 Degrees
1001 9 Orange 315 Degrees Luminance of "2"
0101 10 Light Gray 50% Luminance
1101 11 Pink 0 Degrees, Luminance of "3"
0011 12 Green 225 Degrees
1011 13 Yellow 270 Degrees, Luminance of "3"
0111 14 Aquamarine 180 Degrees, Luminance of "3"
1111 15 White 100% Luminance
Think about Deep Red, Dark Blue, and Purple. You display Deep Red.
Then, you want to display Purple instead of Deep Red. You have to add Dark
Blue to the screen. It is like Deep Red and Dark Blue are joined together
like "OR" to become Purple. Deep Red "OR" Dark Blue = Purple.
Another example, you want Light Blue, but you have to add Luminance over
Purple. Then Purple becomes Light Blue. Purple "OR" Dark Green (With
Luminance) = Light Blue.
One more example. You want to display Ornage. It has Deep Red and
Brown. Deep Red "OR" Brown = Orange. You can see two artifact colors in
one pixel (four dots or pulses as phase shift). Two arfifact colors are
Deep Red and Orange.
It is only a question why Deep Red appears in the left of this pixel.
The answer might be two zero bits between one bit because of no luminance.
It is what I am trying to translate number of degrees to 16 individual
color RGB pixels.
Do you know what I am trying to clarify in details? Do you know the
formula or equation?
Bryan Parkoff