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Size of DOS 3.3 800k volumes?
- Subject: Size of DOS 3.3 800k volumes?
- From: me@lazilong.com (Lazarus I. Long)
- Date: 3 Dec 2002 15:33:18 -0800
- Newsgroups: comp.sys.apple2
- Organization: http://groups.google.com/
- Xref: archiver1.google.com comp.sys.apple2:24956
I know they split into "drive 1" and "drive 2" each 400k.
but is it really exactly 400k? by my calculations it is: 368640
bytes.
256 (bytes/sect) * 16 (sect/track) * 97 (tracks/disk) = 368640
(bytes/disk)
do i have that wrong? does this leave a gap between volumes or are
they separated by the "sides" of the disk? if the disk is separated
by "sides" that would mean, since i must access it as a block device,
when I read block 0, i'm getting 2 sectors, side 0 sector 0 and side 1
sector 0 right?
anyone got any more format info on this?