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Re: Help with confirmation on a small bit of assembly?

Michael J. Mahon wrote:

Raymond Wiker wrote:


"Michael J. Mahon" <mjmahon@aol.com> writes:



Alex Freed wrote:


"Don Bruder" <dakidd@sonic.net> wrote in message
news:45bd5fd9$0$69026$742ec2ed@news.sonic.net...



Yes it does. Take "i" and square it. You'll get a negative -1 by
definition.



OK, wise-guy, any *REAL* number...



Did you ever ask yourself why the numbers in many programming
languages
are devided into INTEGER and REAL?
*REAL* as opposed to IMAGINARY.
So again by definition "i" can not be represented by real numbers.



Eh... I don't  think that holds, seeing as they are, by definition, an
infinite distance apart... Rather difficult for two points an infinite
distance apart to be/occupy the same point, wouldn't you agree?



I would agree if I didn't take a course in the theory of functions of
complex variables. Imaginary numbers are hard to imagine.
Pun intended.



I've always considered the most beautiful math equation to be:

  e^(2*i*pi) = -1

One could teach an entire course in complex analysis from that
equation!




    Not *completely* sure, but I think that's wrong... AFAIR, it
should be e^(pi*i) = -1...



You're right!  e^(2*i*pi) = 0  ;-)


Aaack!  How many times can I mess it up??

e^(2*i*pi) = 1 (not 0 or -1), and, of course

e^(pi*i) = -1 was the equation I meant.

-michael

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