Re: Macintosh LC...need info on this =) TIA

[pausch@saaf.se (Paul Schlyter)]

In article <3A2B32B1.4284BAB4@inetnebr.com>,
Roy and/or Janet Miller  <millers@inetnebr.com> wrote:
> Matt Jenkins wrote:
> 
>> Roy and/or Janet Miller <millers@inetnebr.com> wrote:
> 
>>
>>> The 68000 is generally rated as a 16/32 bit chip (kinda like the 8088
>>> was an 8/16 bit chip)
>>
>> I think you mean 32/24 bit chip.
> 
> No Matt, I meant 16/32. The 68000 had a 16 bit data bus, as the 8088 had
> an 8 bit data bus. The 68000 had 32 bit registers (with, as you mention,
> a 24 bit address space) while the 8088 had 16 bit registers with a 20 bit
> address space. In a similar fashion the 386SX was a 16/32 chip: 16 bit
> data bus, 32 bit registers, 24 bit address space.
 
And then we had the 68008 with an 8-bit externam data bus, which thus
was an 8/32 bit chip.
 
And if you added an 8087 to your 8088, you got 80-bit internal registers
for your floating-point computations, making your 8088+8087 an 8/80-bit
chip combo!
 
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