Re: Higher Frequency Monitor?

["Bryan Parkoff" <nospam@nospam.com>]

> There is no such thing as an NTSC "dot".  There are only
> color artifacts corresponding to the position of a pulse
> relative to the 3.58MHz color subcarrier.  When a series
> of short pulses is interpreted as color, the color displayed
> is not properly a result of the juxtaposition of several
> very small color dots corresponding to each pulse.  The
> whole "constellation" of pulses corresponds to a single
> color dot.
>
> A proper RGB decoding of the Apple II video signal will
> similarly replace a "pixel" constellation with a single
> color pixel as wide as the entire constellation.  To do
> otherwise is to invent new graphics modes.
Michael,

    Thank you for explaining.  I still do not understand what do color
reference mean.  I believe that it means to paint/display number of pixels
in color at 3.5MHz.  Let say for example.

    Deep Red is 1000 bits and Brown is 0001 bits.  Do color reference reads
"1000" before it displays only one deep red pixel in the position 0 while it
displays black pixel in the position 1 through 3?  If second 1000 bits come
after current 1000 bits, it should display deep red pixel in the position 4
while it displays black pixel in the position 5 through 7 before position 1
through 3 has black pixels to become deep red pixels because position 0 and
position 4 are joined together.  Correct?
    Try to think that dark blue and dark green in position 1 and 2 to 
produce medium blue.  Dark green and brown in position 2 and 3 to produce 
light green (HIRES).  Deep red, dark blue, and dark green in position 0 
through 2 to produce light blue.  Dark blue, dark green, and brown in 
position 1 through 3 to produce Aquamarine.  Deep red, dark blue, dark 
green, and brown in position 0 through 3 to produce white.  How can you 
prove to be true?  Think about orange.  Brown in position 3 and deep red in 
position 4 to produce orange.
    Now, do you notice that 0001 bits for brown have black pixel in position
0 through 2 and brown pixel in position 3?  It is how you can see black and
color fringe in the left and right block of low resolution.
    Is it true that Apple II sends only one bit to NTSC monitor at this time
before NTSC displays one out of four dots to produce pixel?  For example,
1100 bits is purple.  Apple II loads one bit which it looks like "1"000
before NTSC monitor displays deep red pixel in position 0.  Then Apple II
shifts next bit which it looks like 0"1"00 before NTSC monitor displays dark
blue pixel in position 1.  Now, position 0 is deep red pixel and position 1
is dark blue pixel which they are joined together to produce purple pixel.
If you look very close at NTSC screen, you will be able to see deep red
pixel in the left behind purple dot and dark pixel in the right behind
purple dot.
    I still don't understand why Apple II is designed to send one bit at
this time instead of four bits.  Please explain.

    Go back to DHR.  I have figured 88 11 22 44 in both aux even/odd and
motherboard even/odd.  Even aux never rotate one byte.  Even motherboard
always rotates one byte to the left three times, odd aux rotates one byte to
the left two times, and odd motherboard rotates one byte to the left one
time.  It would show the string like "10001000100010001000100010001000".  It
is reversed to show "00010001000100010001000100010001" when it displays to
NTSC monitor.
    My question is -- why did Apple Computer, Inc make the decision to
choose 88 instead of 11 in even aux to produce DHGR pixel?  You may notice
that there are black pixels in the far left position before deep red pixel
starts in position 3 through 559.  It is interesting.  I wish that 11 should
be acceptable in aux even to produce deep red.

Bryan Parkoff